Asequence is defined recursively using the formula . if the first term of the sequence is 120, what is f(5)?

F(n+1)=-1/2f(n)

f(n)=-2f(n+1)

given f(1)=120

-2f(1+1)=120

f(2)=-60

f(2)=-2f(2+1)=-60

f(3)=30

f(3)=-2f(3+1)=30

f(4)=-15

f(4)=-2f(4+1)=-15

f(5)=15/2

Hopes it Helps!

f(5)=15/2

Step-by-step explanation:

f(5)=15/2

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

i think the answer is b.

step-by-step explanation:

not 100% sure though.