Saurav sold two radios for rs. 1200 and rs. 1350 respectively. he made a profit of 20% on the first radio and 2% profit on the whole. what was the loss percentage on the second radio ?

Step-by-step explanation:

total sold amount= 1200+1350=2550

profit amount on first radio= 1200-(1200/1.2)=1000

purchase amount of 1st radio= Rs. 1000

total purchased amount= (2550/1.02) = Rs. 2500

purchase amount of second radio=  2500 - 1000 = Rs. 1500

loss % on second radio= ((1500-1350)/1500 ) * 100 = 10%

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1