Suppose that λ is an eigenvalue of a. show that 2λ is then an eigenvalue of 2a.

Proof:

If λ is an eigenvalue of A then for some x≠0,

Which shows that if λ is an eigenvalue of A, 2λ is then an eigenvalue of 2A.

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints

41*67/2=1373.5

step-by-step explanation:

i just used a calculator