Find solution to the system of linear equations. 8x1 + 4x2 = 4 , 4x1 + 2x2 = 2

x1 = -1 and x2 = 3

Step-by-step explanation:

The value of x1 and x2 is gotten by trial and error

When x1 = -1 and x2 = 3

Substitute these values into the first equation

8x1 + 4x2 =4

8(-1) +4(3)

-8 + 12 = 4

4 = 4

Therefore, x1 = -1 and x2 = 3 satisfy the first linear equation

Also, substitute x1 = -1 and x2 = 3 into the second equation

4x1 + 2x2 =2

4(-1) + 2(3)

-4 + 6 = 2

2 = 2

x = -1 and x2 = 3 also satisfy the second linear equation

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation: