Find
∫^[infinity]_-[infinity] x/(1+x^2)^2 dx.

Step-by-step explanation:

integral(x/(1+x^2)^2)dx

=(1/2)integral(2x/(1+x^2)^2)dx

=(1/2)[-1/(1+x^2)] +c

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2

answer: 2530

hope this