What is the length and width of a rectangle if area is 20 and perimeter is 20

a=5+√5

b=5-√5

Step-by-step explanation:

a=?

b=?

P=20

A=20

P=a*b=20

A=a+b=20

ab=20

a+b=10

a=10-b

(10-b)b=20

-b²+10b-20=0

b=-10±√100-80/-2

b=-10±√20/-2

b=-10±2√5/-2

b=-10-2√5/-2=5+√55

b=5-√5

a+b=10

a+5-√5=10

a=5+√5

a+5+√5=10

a=5-√5

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)