Atennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24. the players were still hungry so the coach bought six more hamburgers and two more fries for $16.60. find the cost of each.

The cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

Let "f" be the cost of 1 fries

Let "h" be the cost of 1 hamburger

Given that, tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24

8 x cost of 1 hamburger + 5 x cost of 1 fries = 24

8h + 5f = 24 -------- eqn 1

The players were still hungry so the coach bought six more hamburgers and two more fries for $16.60

6 x cost of 1 hamburger + 2 x cost of 1 fries = 16.60

6h + 2f = 16.60 ------ eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 2

16h + 10f = 48 ------ eqn 3

Multiply eqn 2 by 5

30h + 10f = 83 -------- eqn 4

Subtract eqn 3 from eqn 4

30h + 10f = 83

16h + 10f = 48

( - ) ----------------------

14h = 35

Substitute h = 2.5 in eqn 1

8(2.5) + 5f = 24

20 + 5f = 24

5f = 4

Thus cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.