Aspinner with 9 equal sections is numbered 1 through 9. the probability of spinning a 3 is
what is the probability of not
spinning a 3?
enter your answer as a fraction, in simplest form, in the box.

show your answer

Step-by-step explanation:

Numbers 1 thru 9... probability of spinning a 3 is 1/9 and the probability of not spinning a 3 is 8/9

1/9, 8/9

Step-by-step explanation:

probability of a desired outcome =

= (number of desired outcomes)/(total number of outcomes)

The total number of outcomes is 9.

(a) The probability of spinning a 3

There is only 1 desired outcome, a 3.

p(3) = 1/9

(b) What is the probability of not  spinning a 3?

The probability of spinning a 1, 2, 4, 5, 6, 7, 8, or 9.

There are 8 desired outcomes.

p(not 3) = 8/9

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!