Figure 8.2. use this table with the question(s) below, as needed.
monthly payment on a $100 loan
term in
annual percentage rate
months 15.00% 16.00% 17.00% 18.00%
17.40 17.45 17.50 17.55
9.03 9.07
9.12
9.17
6.24 6.29 6.33 6.38
4.85
4.94 4.99
4.02 4.07
4.11
4.16
3.47
3.52 3.57 3.62
3.07 3.12 3.18 3.23
2.78 2.83 2.89 2.94
54
2.56 2.61
2.72
4.90
2.66
2. use figure 8.2. macon steinberg purchased a motor scooter with an installment loan that has an apr of 16
percent. the motor scooter sells for $1,687. the store financing requires a 20 percent down payment and 30
monthly payments. what is the finance charge?
a. $300.98
c. $325.00
b. $298.90
d. $312.13

22 dimes and 9 nickels

step-by-step explanation:

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

that one look

step-by-step explanation: