Proving triangle similarity
given: nm / xz
prove: axyz - anym
we know that side nm is
to side xz. if
we consider side ny the transversal for these parallel
lines, we create angle pairs. using the
, we can state that
zyxz is congruent to zynm. we know that angle
xyz is congruent to angle h y by the reflexive
property. therefore, triangle xyz is similar to triangle
nym by the similarity theorem.
1) intro
done

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

answer: (1,3) (3,-1) (5,-5) ?

step-by-step explanation:

it's undefined because anything multiplied by 0 is 0. that said, 7 days is 168 hours