In a survey of 300 college graduates, 63% reported that they entered a profession closely related to their college major. if 9 of those survey subjects are randomly selected without replacement for a follow-up survey, what is the probability that 4 or fewer of them entered a profession closely related to their college major?
a)0.793

b)0.0512

c)0.149

d)0.207

D) 0.207

Step-by-step explanation:

Binomial probability:

P = nCr pʳ qⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1−p).

Here, n = 9, p = 0.63, and q = 0.37.

If r = 4:

P = ₉C₄ (0.63⁴) (0.37⁹⁻⁴)

P = 0.1376

If r = 3:

P = ₉C₃ (0.63³) (0.37⁹⁻³)

P = 0.0539

If r = 2:

P = ₉C₂ (0.63²) (0.37⁹⁻²)

P = 0.0136

If r = 1:

P = ₉C₁ (0.63¹) (0.37⁹⁻¹)

P = 0.0020

If r = 0:

P = ₉C₀ (0.63⁰) (0.37⁹⁻⁰)

P = 0.0001

The total probability is:

P = 0.1376 + 0.0539 + 0.0136 + 0.0020 + 0.0001

P = 0.2072

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

happy to

pls mark as brainliest

tell you what. i'll find the length of the medians and you can fill in the blanks where they belong.

br

b = (2a,0)

r = (a/2,b/2) remember these things are medians. they go to the 1/2 way point of the line opposite the vertex they face.

br^2 =   (2a - a/2)^2 + (0 - b/2)^2

br^2 = (3/2 a) ^2 + b^2 / 4

br^2 = 9/4 a^2 + b^2 / 4   we need to find some relationship between a and b.

let's try ab = bc  

ab = 2a

bc = (2a - a)^2 + (b - 0)^2

bc = sqrt(a^2 + b^2)

ab = bc

2a = sqrt(a^2 + b^2) square both sides.

4a^2 = a^2 + b^2 subtract a^2 from both sides.

sqrt(3a^2) = sqrt(b^2)

sqrt(3)a = b

let's put b into br^2

br^2 = 9/4 a^2 + 3b^2 / 4

br^2 = 12 a^2 / 4

br^2 = 3a^2 

br = sqrt(3) * a

cp

c = (a,b) ; p = (a,0) this is another application of the distance formula, and it is a good one.

cp^2 = (a - a)^2 + (b - 0)^2

cp^2 = 0 + b^2

cp^2 = b^2 which you can see from the diagram. 

cp = sqrt(b^2)

cp = b but b = sqrt(3) * a 

cp = sqrt(3)*a

aq

a = (0,0)

q = (3/2) a, b/2

aq^2 = (3a/2 -0)^2 + (b/2 - 0)^2

aq^2 = 9a^2/4 + b^2/4

but b = sqrt(3) * a 

aq^2 = 9a^2 / 4 + (sqrt(3)*a)^2 /4

aq^2 = 9 a^2/ 4 + 3 a^2 / 4

aq^2 = 12 a^2/4

aq^2 = 3 a^2

aq = (sqrt  3) * a which agrees with the other two.