Y=x2 +6x-2
write each quadratic in vertex form by completing the square. then identify the quadratic’s turning point

see explanation

Step-by-step explanation:

The equation of a quadratic in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Given

y = x² + 6x - 2

To complete the square

add/ subtract ( half the coefficient of the x- term )² to x² + 6x

y = x² + 2(3)x + 9 - 9 - 2

  = (x + 3)² - 11 ← in vertex form

with (h, k) = (- 3, - 11 )

Turning point = (- 3, - 11 )

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

sorry i need the points

step-by-step explanation:

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