2. the number of nickels that christine has is
5 times the number of dimes. their value is
$1.05. how many coins of each type does
she have?

The number of nickels is  15

The number of Dimes is 3

Step-by-step explanation:

Let the number of dimes  Christine has be d

The number of nickels with christine be n

Then the number of Nickels  Christine has will be  

n = 5d ----------------------------------(1)

Now The total value of both dimes and nickels is  = $1.05

This can be represented as

5n +10d = 105  (in cents)

From eq(1)

5(5d) + 10d = 105

25d+10d = 105

35d = 105

d = 3----------------------------------(2)

Substituting (2) in (1), we get

n = 5(3)

n = 15

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116