Alocal restaurant recently renovated its dining space, purchasing new tables and chairs to use in addition to the original tables and chairs. the new tables seat 6 customers, while the original tables seat 4 customers. altogether, the retaurant now has 40 tables and is capable of seating 220 customers. how many more new tables than original tables does the restaurant have?

20

Step-by-step explanation:

The new table seats 6 customers

The original table seats 4 customers

Total number of tables = 40

Total number of customers capable of seating = 220

Let new tables = x

Let original tables = y

x + y = 40 (1)

6x + 4y = 220 (2)

From equation (1)

x + y = 40

x = 40 - y (3)

Put eq(3) into eq(2)

6(40 - y) + 4y = 220

240 - 6y + 4y = 220

240 - 2y = 220

-2y = 220 - 240

-2y = -20

y = -20/ -2

y = 10

Put y=10 into eq(3)

x = 40- 10

x = 30

To find how many more new tables than the original table the restaurant has, we will subtract the number of original tables from new ones.

y - x

= 30 -10

= 20

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3