(05.02)an artist is designing a kite like the one show below. calculate the area to determine how much material she will need to create the kite. a kite with two top triangles with height of 6 inches and a base 8.5 inches. the bottom two triangles share the base but have a height labeled 13 inches. 36 square inches 110.5 square inches 161.5 square inches correct answer 323 square inches

161.5 in.^2

Step-by-step explanation:

Since you don't have a figure, from your description, I understand that the base of each small upper triangle is 8.5 inches. That means that each small triangle on top has a base of 8.5 inches and a height of 5 inches, and each small triangle below has a base of 8.5 inches and a height of 13 inches. My calculations below are base don this understanding.

The area of a kite is

A = (Bb)/2

where B and b are the lengths of the diagonals.

The diagonals have lengths:

B = 13 in. + 6 in. = 19 in.

b = 8.5 in. + 8.5 in. = 17 in.

A = (Bb)/2

A = (19 in. * 17 in.)/2

A = (323 in.^2)/2

A = 161.5 in.^2

the central idea is that:

individuals should refuse to cooperate with institutions they believe unjust.

thoreau felt  that governments were more often agents of corruption than justice, even democracies, and that just because the majority feels a certain way does not make it just or correct in absolute terms. he uses the fact that slavery exists in our democracy to support this idea.

he goes on to say that, as a result, people should live true to their own internal laws regarding right and wrong, as a product of reflection and a moral life, rather than following every law that society imposes. 

step-by-step explanation:

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}