Match each interval with the corresponding rate of change for the function h(x) = 2–x on the interval.

1. 0 ≤ x ≤ 2
–1.
2. –1 ≤ x ≤ 0
–1.5000
3. 0 ≤ x ≤ 1
–0.9375
4. –2 ≤ x ≤ –1
–2.
5. –2 ≤ x ≤ 0
–0.3750
6. –2 ≤ x ≤ 2
–0.5000

oof

step-by-step explanation:

hi there!

question 1 answer: p/q can be terminating when q = 5^m * 2^n

question 2 answer: -1 and -1

question 3 answer: -4

question 4 answer: 5/12

hope this : )

the answer is a.

135 and 80

step-by-step explanation: