Aperson at mart has decided that they would like to completely fill the ball bin in the toy section with one type of ball. the ball the stock person decided to use had a radius of 2 m. the ball bin is 3.2 meters tall and the opening at the top is 1 meters by 1.5 meters. how many balls should fit inside the bin?
(hint: packing spheres in a rectangular prism usually take up 190% of the volume of the spheres

No balls

Step-by-step explanation:

Given:

The radius of the ball = 2 m

Height of the ball bin  = 3.2 metres

Length of of the ball bin = 1 meters

Width of the ball bin  = 1.5 metres

To Find:

How many balls should fit inside the bin = ?

Solution:

Step 1: Finding the volume of the ball

The volume of the ball =

Substituting the value,

=>

=>

=>

=> 33.49

=>33.5 cubic meters

Step 2: Finding the packing space per ball

=>

=>

=>

=> cubic meters

Step 3: Finding the volume of the container

The volume of the rectangular prism (packing box )

=>

=>

=>4.8 cubic meters

Step 4: Finding the number of ball that can fit in the container

Number of ball   =

Number of ball   =

Number of ball   = 0.07

No balls can be packed in the bock since the volume of the box is lesser than the packing space required per ball

ddsf

step-by-step explanation:

dfs

your exact question is kind of difficult to understand, so maybe an example will explain what you're supposed to do? i'll work through the first problem on the worksheet.

suppose you have a tray of 652 brownies, and you have 5 friends that you want to feed without picking favorites. how many brownies can you dole out to each of your friends in equal amounts? how many will be left over for you to eat?

what you're doing here is finding a way to arrange the number 652 as the sum of integer multiple of 5 and some remainder:

here ("q" for quotient) is the number of brownies each of your friends get, and is the remainder. that's the basic idea behind division.

we break up the number 652 into parts so that the leading digit stands on its own:

652 = 600 + 52

first we check if it's possible to hand out exactly 100 brownies to each friend. with 5 friends, this means we want to know if we can take out 500 brownies from the tray. we can do this 1 time because we have 600 brownies to take from, and when we do that we're left with 100 + 52 brownies to divvy up. so we know that

652 = 1*500 + 152

next we want to know if it's possible to hand out exactly 10 brownies per friend. if we can, we have to remove 50 brownies from the tray each time until we can't. we have 152 brownies left, and we know that 3(50) = 150, so

152 = 3*50 + 2

now we have 2 brownies left in the tray. is it possible to hand 1 out to each of your 5 friends? no, you'd need a minimum of 5 brownies to do that. so the last 2 are yours.

putting everything together, we found that

652 = 1*500 + 3*50 + 2

and we can rearrange this to write

652 = 5*100 + 5*30 + 2

652 = 5(100 + 30) + 2

652 = 5*130 + 2

so and .

you might be more accustomed to the table depicting the algorithm. that's just a compact way of organizing what we've done above. you can consult the image i've attached below.