Ineed with this problem, can someone ?

By AAS criteria Δ ABC ≅ Δ ADC

Step-by-step explanation:

See the diagram attached.

We have to prove Δ ABC ≅ Δ ADC

Steps :  

Between Δ ABC and Δ ADC

1. CA bisects ∠ BAD, and hence, ∠ CAB = ∠ CAD {Given}

2. ∠ B = ∠ D {Given}

3. Side AC is common to both the triangles.

Hence, by Angle-Angle-Side i.e. AAS criteria Δ ABC ≅ Δ ADC (Proved)

what does x eaqual

step-by-step explanation:

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation: