The center of a circle is on the line y =2x and the line x=1 is tangent to the circle at (1, 6).
find the center and radius of the circle.

Step-by-step explanation:

slope of line perpendicular to x=1 is zero

eq. of line perpendicular to x=1 passing through (1,6) is

y-6=0(x-1)

or y-6=0

or y=6

to find the point of intersection of y=6 and y=2x

2x=6

x=3

so center is (3,6)

radius=√[(3-1)²+96-6)²]=2

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.