Suppose 60% of jurors come to a just decision. in a jury of ten people, what is the probability more than half come to a just decision?

a. 0.3669
b. 0.3823
c. 0.6177
d. 0.6331
e. 0.8494

D. 0.6331

Step-by-step explanation:

Use binomial probability:

P = nCr pʳ qⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is 1−p, the probability of failure.

More than half of 10 jurors is 6, 7, 8, 9, and 10.  Find the probability of each.

If r = 6:

P = ₁₀C₆ (0.6)⁶ (0.4)⁴

P = 0.2508

If r = 7:

P = ₁₀C₇ (0.6)⁷ (0.4)³

P = 0.2150

If r = 8:

P = ₁₀C₈ (0.6)⁸ (0.4)²

P = 0.1209

If r = 9:

P = ₁₀C₉ (0.6)⁹ (0.4)¹

P = 0.0403

If r = 10:

P = ₁₀C₁₀ (0.6)¹⁰ (0.4)⁰

P = 0.0060

Therefore, the total probability is:

P = 0.2508 + 0.2150 + 0.1209 + 0.0403 + 0.0060

P = 0.6330

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)