Prove that the points (3,,7) and (9,3) are the vertices of a right triangle

The points (3,3), (3,7) and (9,3) do not form a right angled triangle

Solution:

Given vertices of triangle are (3, 3) , (3, 7) and (9, 3)

Let the triangle be ABC

Let the vertices be,

A = (3, 3)

B = (3, 7)

C = (9, 3)

For a triangle to be right angled triangle, it must obey Pythagoras theorem

Pythagorean theorem, states that the square of the length of the hypotenuse is equal to the sum of squares of the lengths of other two sides of the right-angled triangle.

Therefore by above definition,

Let us use the distance formula

The distance between A and C is given as:

Therefore,

Thus length of AC is 6 units

The distance between A and B is given as:

The distance between B and C is given as:

Thus by Pythagorean theorem,

Substituting the obtained values we get,

Thus the vertices does not form a right angled triangle

answer: the answer is ann

11.2

step-by-step explanation:

when doing tangent the tangent of the angle is equal to the opposite side from the angle over the adjacent side to the angle.

tan43 = x / 12

move 12 over by multiplying each side by 12

12tan43 = x

x = about 11.2