The population of a small town is 39,668 and has been continuously declining at a 1.5% a year what will the population be in 13 years

 31, 932.74

Step-by-step explanation:

The population of the small town              =  39,668

Yearly rate of decline                                 = 1.5%

Therefore, to calculate 1.5% of 39,668       = 1.5  x 39,668

                                                                                  100

                                                                      =   595.02

So, the population is declining by 595.02 on yearly basis.

To ascertain what will the population would have declined to in the next 13 years,

We multiply ,                                                = 595.02 x 13

                                                                      =7,735.26

Now population in 13 years                         = 39,668 - 7,735.26

                                                                      = 31,932.74

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}