Acertain company has 18 equally qualified applicants for 4 open positions.
how many different groups of 4 applicants can be chosen by the company to fill the positions if the order of selection does not matter?

a) 18 b) 72 c) 180 d) 1,260 e) 3,060

E) 3,060

Step-by-step explanation:

Given : The total number of equally qualified applicants = 18

The number of positions = 4

If order of selection does not matter , then we use combinations.

So , the number of different groups of 4 applicants can be chosen by the company to fill the positions =  

[ ∵ ]

Therefore , the number of different groups of 4 applicants can be chosen by the company to fill the positions if the order of selection does not matter = 3,060.

Therefore , the  correct answer is E) 3,060

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option