Ms. wang is shopping for a new refrigerator. brand a costs $569 and uses 635 kilowatt-hours per year. brand b costs $647 and uses 582 kilowatt-hours per year. if electricity costs $0.18 per kilowatt-hour, how much would ms. wang save on electricity per year by buying brand b?

Savings on electricity per year by brand B = 114.3 - 104.76 = $9.54

Step-by-step explanation:

Ms. Wang is shopping for a new refrigerator. Brand A costs $569 and uses 635 kilowatt-hours per year. Brand B costs $647 and uses 582 kilowatt-hours per year.

Let's assume he buys brand B, so he already has a loss over the price of the commodity that is , loss = 647 - 569 =$78

Cost of electricity = $0.18

Now in the case of electricity,

spending on Brand A = 635 0.18 = $114.3

spending on Brand B = 582 0.18 = $104.76

Savings on electricity per year by brand B = 114.3 - 104.76 = $9.54

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: