Mr. jones has part of his $5,000 savings in an account that earned 7% interest and the rest in an account that earned 9% interest. how much did he have in each account if his annual income from the total investment was 404.27? use z for the 7% account and y for the 9% account.

z = $2286.5

y = $2713.5

Step-by-step explanation:

Let z represent the amount of money invested at the rate of 7%.

Let y represent the amount of money invested at the rate of 9%.

Mr. Jones has part of his $5,000 savings in an account that earned 7% interest and the rest in an account that earned 9% interest.. This means that

z + y = 5000

The formula for simple interest is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time

Considering the investment at the rate of 7%,

P = x

R = 7

T = 1

I = (z × 7 × 1)/100 = 0.07z

Considering the investment at the rate of 9%,

P = y

R = 9

T = 1

I = (y × 9 × 1)/100 = 0.09y

if his annual income from the total investment was 404.27, it means

0.07z + 0.09y = 404.27 - - - - - -1

Substituting z = 5000 - y into equation 1, it becomes

0.07(5000 - y) + 0.09y = 404.27

350 - 0.07y + 0.09y = 404.27

- 0.07y + 0.09y = 404.27 - 350

0.02y = 54.27

y = 54.27/0.02 = $2713.5

Substituting y = 2713.5 into z = 5000 - y, it becomes

z = 5000 - 2713.5 = $2286.5

water molecules will move from the side of higher water concentration to the side of lower concentration until both solutions are isotonic. at this point, equilibrium is reached. in an isotonic solution, the flow of water in and out of the cell is happening at the same rate.

hope this < 3

answer: x

step-by-step explanation: