Several guys went to eat lunch at subway
and bought four cold drinks and seven
subway sandwiches for $21.60. joseph and
his date had two cold drinks and three
subway sandwiches. if the sandwiches cost
twice as much as the cold drinks, how much
was joseph's bill?
write 2 systems of

Joseph's bill was $9.6.

Step-by-step explanation:

Given:

Number of cold drinks  = 4

Number of subway sandwiches = 7

Total cost of cold drinks and sandwiches = $21.60

The sandwiches cost  twice as much as the cold drinks

To Find:

How much  was Joseph's bill = ?

Solution:

Let the cost  of one cold drink be x

The cost of  sandwich be y

The sandwiches cost  twice as much as the cold drinks

then

y = 2x--------------------------------------(1)

Now the total amount can be represented as

4x+7y =21.60-----------------------------(2)

Substituting (1) in (2)

4x+7(2x) =21.60

4x+14x =21.60

18x =21.60

x = 1.2--------------------------------------(3)

The cost of one cold drink is $1.2

On substituting (3) in(1)

y = 2(1.2)

y = 2.4

The cost of one sandwich is $2.4

Now ,Joseph and  his date had two cold drinks and three Subway sandwiches.  So Joseph bill will be

=>

=>

=>(2.4) + (7.2)

= 9.6

your answer is 40

step-by-step explanation:

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47