2. when a person is selected at random from a very large population, the probability that the selected person is righthanded is 0.82. if three people are selected at random,
what is the probability that
a. they are all right-handed?
b. none of them is right-handed?

a) 0.5514

b) 0.0058

Step-by-step explanation:

Data provided in the question:

Probability that the  the selected person is righthanded, P(R) = 0.82

Therefore,

Probability that the  the selected person is not righthanded, P(R') = 1 - 0.82

= 0.18

Now,

a. They are all right-handed

P (They are all right-handed) = P(R) × P(R) × P(R)

= 0.82 × 0.82 × 0.82

= 0.5514

b) None of them is right-handed

P (None of them is right-handed) = P(R') × P(R') × P(R')

= 0.18 × 0.18 × 0.18

= 0.0058

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step-by-step explanation:

the answer is d. (1.2, -4.7) on edgn

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