3. could the circle with equation x^2−6x+y^2−7=0 have a radius of 4? why or why not?

Yes, it has a radius of 4

Step-by-step explanation:

General equation of a circle is

x²+y²+2gx+2fy+c = 0... 1

Where r = √g²+f²-c

Comparing the general b equation to the given equation to get g, f and c

x^2−6x+y^2−7=0

Rearranging

x²+y²-6x -7 = 0... 2

Comparing 1 and 2;

2gx = -6x

2g = -6

g = -3

2fy = 0 ( since there is no function of y in the given equation)

f = 0

c = -7

Substituting into the radius formula

r = √(-3)²+0² -(-7)

r = √9+7

r = √16 units

r = 4units

It is true that the radius of the circle is 4units

goog may have it for you

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column