Asurvey of 100 people, each of whom owns a dog or a cat or both, showed that 63 own a dog and 58 own a cat. based on these results, how many of the people surveyed own both a cat and a dog?

Step-by-step explanation:

For this case we have a total of people given 100

Let's define some notation:

C= Represent the people with just cats

D= Represent the people with just dogs

T=  Represent the total os people

For this case we know that C = 58 ,D = 63 and T =100

The total on this case represent the union of both events CUT. And from the total general rule we have this

CUT = C + T - (C intersection D)

From the last formula we can find the interection between C and D who represent the people surveyed own both a cat and a dog.

C intersection D= C+ T + (CUT) = 58+63-100=21

And that represent the final answer for this case as we can see on the figure attached.

We can find also the people with just dogs 63-21= 42

And the people with just one cat 58-21= 37.

518,400

step-by-step explanation:

the area is multiplying all the given measurements together.

40 * 18 * 30 * 24 = 518,400

three-fourths of an hour

36÷48=0.75

0.75=