If street lights are placed at most 150 feet apart, how many street lights will be needed for a street that is 2 miles long, assuming that there are lights at each end of the street?

We need 741 street lights for a street that is 2 miles long .

Step-by-step explanation:

We know that 1 mile = 5280 feet

Then, 2 miles = 2 x 5280 = 10560 feet

Given : Street lights are placed at most 150 feet apart.

Then, the number of intervals in 2 miles long street = 2 miles ÷ 150

=(10560 feet)  ÷ 150

= 70.4 ≈ 70  [The distance between streets cannot be greater than 150 feet.]

If there are lights at each end of the street , then we need to starts from one end .

Total lights = Number of interval +1

=70+1  =71

Hence, we need 741 street lights for a street that is 2 miles long .

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

step-by-step explanation:

infinity is the answer