Write the standard form of the equation that passes through the point (-2, 4) and is parallel to x - 2y = 6. include your work in your final answer. type your answer in the box provided or use the upload option to submit your solution.

The equation of line passing through point ( - 2 , 4) with slope parallel to given line is   y =   x + 5

Step-by-step explanation:

Given as :

The equation of line is x - 2 y = 6

Or, 2 y = x - 6

Or, y = × x -  

i.e y = × x -  3

Now, Standard equation of line in slope-intercept form

y = m x + c

where m is the slope of line

And c is the y-intercept

Now, Compare given line with standard line equation

So, The slope of line y = × x -  3 = m =

Again

Other line is passing through points ( - 2 , 4) and is parallel to given line

∵ For parallel lines condition

The slope of both lines are equal

Let The slope of other line = M

So, from condition

M = m =  

Now, equation of line passing through point ( - 2 , 4) with slope  

So, Equation of line in slope-point form

y - = M × (x - )

Or, y - 4 =   × (x - ( - 2) )

Or, y - 4 =   × (x + 2 )

Or, y = × (x + 2 ) + 4

Or, y =   × x +   × 2 + 4

Or, y = × x +   + 4

∴   y =   × x + 1 + 4

i.e y =   x + 5

So, Equation of other line  y =   x + 5

Hence, The equation of line passing through point ( - 2 , 4) with slope parallel to given line is   y =   x + 5 . Answer

75

step-by-step explanation:

u bout ugly as   a mf

step-by-step explanation: lol