Drag the tiles to the correct boxes to complete the pairs.
match the statements with their values.

1.m ∠abc + m∠bac + m∠acb
when δabc is an isosceles triangle with

2. m∠abc when m∠bac = 70°
and δabc is an isosceles triangle with

3. m∠qpr when m∠qrp = 30°
and δpqr is an isosceles triangle with

4. m∠bde when m∠bac = 45°
and points d and e are the midpoints of
and , respectively, in δabc

1. 55°
2. 180°
3. 45°
4. 30°

Part 1) Option 2. 180°

Part 2) Option 1. 55°

Part 3) Option 4. 30°

Part 4) Option 3. 45°

Step-by-step explanation:

Part 1) Determine

m ∠ABC + m∠BAC + m∠ACB

Remember that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

In this problem

The sum of the three interior angles of triangle ABC must be equal to 180 degrees

so

m ∠ABC + m∠BAC + m∠ACB=180°

Part 2) Determine m∠ABC

when m∠BAC = 70°  and ΔABC is an isosceles triangle with AB=AC

In this problem the vertex angle is m∠BAC = 70°

m∠ABC=m∠ACB ---> because AB=AC

Remember that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

2m∠ABC+m∠BAC=180°

substitute the given values

2m∠ABC+70°=180°

2m∠ABC=180°-70°

2m∠ABC=110°

m∠ABC=55°

Part 3) Determine m∠QPR

when m∠QRP = 30°  and ΔPQR is an isosceles triangle with  PQ=QR

In this problem

m∠QPR=m∠QRP ---> because PQ=QR

we have

m∠QRP = 30° ---> given problem

therefore

m∠QPR = 30°

Part 4) Determine m∠BDE      

when m∠BAC = 45° and points D and E are the midpoints of AB and BC in ΔABC

we know that

Segment DE is parallel to segment AC (because the points D and E are the midpoints of segment AB and BC

so

m∠BDE=m∠BAC > by corresponding angles

we have

m∠BAC = 45° ---> given problem

therefore

m∠BDE = 45°

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

i think the answer is b.

step-by-step explanation:

not 100% sure though.