The perimeter of a triangle is 93 ft. side a of the triangle is twice as long as side b. side c is 3 ft longer than side a. find the length of each side.

The length of side a is 36 feet and side b is 18 feet and side c is 39 feet

Solution:

Given that perimeter of triangle is 93 feet

The three sides of triangle are a, b, and c

Given that Side a of the triangle is twice as long as side b

side a = 2 times side b

a = 2b

 ---- eqn 1

Given that Side c is 3 ft longer than side a

side c = 3 + side a

c = 3 + a ------ eqn 2

The perimeter of triangle is given as:

p = a + b + c

Where a, b, c are the length of sides of triangle

Substitute eqn 1 and eqn 2 in above formula

Given that perimeter = 93

Thus length of side a = 36 feet

Length of side b :

from eqn 1

b = 18 feet

Length of side c:

From eqn 2,

c = 3 + 36 = 39

c = 39 feet

Thus length of side a is 36 feet and side b is 18 feet and side c is 39 feet

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