Find two consecutive even numbers such that the difference of one-half the larger number and two-fifths the smaller number is equal to five. 38 and 40 40 and 42 42 and 44

The two consecutive even numbers are 40 and 42

Solution:

Let the two consecutive even numbers be x and x + 2

Let "x" be the smaller number and "x + 2" be the larger number

Given that difference of one-half the larger number and two-fifths the smaller number is equal to five

So we can frame a equation as,

one-half the larger number - two-fifths the smaller number = 5

Thus x = 40

And x + 2 = 40 + 2 = 42

Thus the two consecutive even numbers are 40 and 42

aloha~! my name is zalgo and i am here to you out on this amazing day. to answer your question, yes, nonzero numbers can have a greatest common factor and that would be 1. still don't get it? let me considering every number is divisible by 1 and hence every number has 1 as a factor of theirs. so, if 2 nonzero numbers didn't share any gcf (greatest common factor), they would still have a factor in common and that would be 1.

i hope that this ! : p

"stay and stay proud! " - zalgo

(by the way, do you mind marking me as brainliest? i'd greatly appreciate it! mahalo! x3)