Apool 8ft wide and 25ft long was being filled with water. at 10: 00 a. m the depth of the water was 2ft, at 3: 00 p. m it was 5ft, how full will it be at 10: 00 a. m

  2 ft   or   16.4 ft

Step-by-step explanation:

The problem statement tells you the pool is 2 ft deep at 10:00 am.

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The depth changes 3 ft in the 5 hours between 10 am and 3 pm, so is changing at the rate of 3/5 ft/hour. In 24 hours, it will change (3/5)(24) = 14.4 ft. Added to the 2 feet of depth at 10 am, the depth at the next instance of 10 am will be 16.4 ft.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet