Find the 4^\text{th}4 th 4, start superscript, start text, t, h, end text, end superscript term in the sequence.

If the sequence is the following:

c(n) = -7+6 (n-1)

c(1) = -7 + 6(1-1) = -7 + 6(0) = -7+0 = -7

c(2) = -7 + 6(2-1) = -7 + 6(1) = -7 +6 = -1

c(3) = -7 + 6(3-1) = -7 + 6(2) = -7 + 12 = 5

c(4) = -7 + 6(4-1) = -7 + 6(3) = -7 + 18 = 11

Step-by-step explanation:

If the sequence is the following:

c(n) = -7+6 (n-1)

And we want to find the first four terms, so w ejust need to replace the values for n =1,2,3,4 and see what we got:

c(1) = -7 + 6(1-1) = -7 + 6(0) = -7+0 = -7

c(2) = -7 + 6(2-1) = -7 + 6(1) = -7 +6 = -1

c(3) = -7 + 6(3-1) = -7 + 6(2) = -7 + 12 = 5

c(4) = -7 + 6(4-1) = -7 + 6(3) = -7 + 18 = 11

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the aswere is the one with all 8's and the second one is with the 10,8 and 6

step-by-step explanation: