In the air, it had an average speed of 16 \text{m/s}m/sstart text, m, slash, s, end text. in the water, it had an average speed of 3 \text{m/s}m/sstart text, m, slash, s, end text before hitting the seabed. the total distance from the top of the cliff to the seabed is 127 meters, and the stone's entire fall took 12 seconds.

Time in air = 1.89 seconds and time in water = 10.11 seconds

Step-by-step explanation:

We have to find the time duration through which it travelled in both air and water.

It had an average speed of 16 m/s in air and 3 m/s in water. Also the total distance travelled = 127 meters.

The total time of fall of the rock = 12 seconds .

The time in each medium is inversely proportional to the speed in that medium.

The time taken in each medium will be in the inverse ratio of the time taken.

Let time in air and water be .

=

Also = 12

Solving the two equations we get,

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.