In how many arrangements can a teacher seat 3 girls and 3 boys in a row of 6 seats if the boys are to have the first, third, and fifth seats?

36 ways.

Step-by-step explanation:

There are  3 seats available to the 3 girls.

So we need to find the number of ways  we can arrange 3 girls.

This is 3!  which works out to 3*2*1 = 6 ways.

Now the 3 boys can also be arranged in 6 ways in their 3 seats.

So the total number of arrangements are 6*6 = 36.

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.