Write an equation in slope-intercept form for the line that passes through the point  ( -1 , -2 )  and is perpendicular to the line − 4 x − 3 y  =  − 5

The equation in slope-intercept form for the line that passes through the point  ( -1 , -2 )  and is perpendicular to the line − 4 x − 3 y  =  − 5 is

Solution:

The slope intercept form is given as:

y = mx + c ----- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given that the line that passes through the point  ( -1 , -2 )  and is perpendicular to the line − 4 x − 3 y  =  − 5

Given line is perpendicular to  − 4 x − 3 y  =  − 5

− 4 x − 3 y  =  − 5

-3y = 4x - 5

3y = -4x + 5

On comparing the above equation with eqn 1, we get,

We know that product of slope of a line and slope of line perpendicular to it is -1

Given point is (-1, -2)

Now we have to find the equation of line passing through (-1, -2) with slope

Substitute (x, y) = (-1, -2) and m = 3/4 in eqn 1

Thus the required equation of line is found

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²

-81 -56 -27 0 81

step-by-step explanation: