12. the sum of three consecutive integers is 12 more than twice the largest integer. which of the following
equations could be used to find the three integers?

(1) n+n+1+n+2 = 2n +2+12
(2) n+n+2+n+4 = 2(n + 4)+12
(3) n+n+1+n+3 = 2n +3+12
(4) n+n+1+n+2 = 2(n + 2) +12

OPTION 4

Step-by-step explanation:

Let the three consecutive numbers be n, (n + 1) and (n + 2).

Note that the largest number of the three is (n + 2) and the smallest is n.

So, according to the given data, the sum of all the three integers is equal to 1 more than twice more than the largest number.

Writing it mathematically, we have:

n + (n + 1) + (n + 2) = 12 + 2(n + 2)

This is OPTION (4) and is the answer,

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.

english, cause i can’t you