If x is to be chosen at random from the set {1,2,3,4} and y is to be chosen at random from the set {5,6,7},what is the probability that xy will be even?

2/3

Step-by-step explanation:

To get the answer here, firstly we would need to know the total number of expected answer. This is equal to 12. This can be gotten by using a table whereby one of the parameters are on the horizontal side with the other on the vertical.

Now the even numbered products are : 6, 10,12,14,18,20,24 and 28

The total number of this is 8

The probability is thus 8/12 = 2/3

23

step-by-step explanation:

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: