How many positive integer values of x are possible to solve the equation 5x²+3y+2.

Step-by-step explanation:

I would divide the answer in two parts

part A

If the given equation is correct, then the equation has no answer

Process

let y = 0 then 5x^2 + 2 = 0. We subtract 2 from both sides 5x^2= -2.

Now we divide each side by 5 and apply square root property

x^2=-2/5  --> x=square root(-2/5). Therefore, the equation has no solution. Complex solution.

Part B

If the given equation is not correct (the exercise is badly copied), then the correct exercise would be 5x^2+3x-2=0

We can solve the polynomial using quadratic formula, and we will obtain

x=-1 and x=2/5.

So the answer X cannot be integer.

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)