Helen plays basketball. for free throws, she makes the shot 78% of the time. helen must now attempt two free throws. c = the event that helen makes the first shot. p(c) = 0.78. d = the event helen makes the second shot. p(d) = 0.78. the probability that helen makes the second free throw given that she made the first is 0.86. what is the probability that helen makes both free throws?

0.6708 or 67.08%

Step-by-step explanation:

Helen can only make both free throws if she makes the first. The probability that she makes the first free throw is P(C) = 0.78, now given that she has already made the first one, the probability that she makes the second is P(D|C) = 0.86. Therefore, the probability of Helen making both free throws is:

There is a 0.6708 probability that Helen makes both free throws.

14

step-by-step explanation:

15: 24

62.5%

step-by-step explanation: