8. (07.01 mc)
if the sin 0° = 0, then which statement is true? (6 points)
o
cos 90º = 1, because the cosine and sine are complements
cos 180°
1, because the cosine and sine are supplements
cos 90º = 0, because the cosine and sine are complements
o
cos 180º = 0, because the cosine and sine are supplements

, because the cosine and sine are complements

Step-by-step explanation:

Sine and cosine are trigonometric complementary functions. If we are talking about a right triangle we will have the following:

(1)

(2)

Let's prove it:

(3)

(4)

(5)

(6)

cos 90° = 0, because the angles are complements

Step-by-step explanation:

cos 90° = 0

sin 0° = 0

sin and cos are complementary

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

b

step-by-step explanation:

it have 5 sides and 5 identicle angle.the rest does not have the same property as b.

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