65pts
part 1. create two radical equations: one that has an extraneous solution, and one that does not have an extraneous solution. use the equation below as a model:
a√x+b+c=d
part 2. show your work in solving the equation. include the work to check your solution and show that your solution is extraneous.
part 3. explain why the first equation has an extraneous solution and the second does not.

part a)

for extraneous solution

1 ⋅ sqrt(x+2) + 3 = 0

for non extraneous solution

1⋅ sqrt(x+2)  + 3 = 6

part b) solve each equation

1⋅sqrt(x+2)+3=0

x+sqrt(x+2)=−3

square both sides

(sqrt(x+2))^ 2 = (−3)^2

x+2=9

x=9−2

x=7

Step-by-step explanation:

is there any photos or whatever?

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)