Find the smaller of two consecutive integers, x, if the sum of the smaller and two times larger is 14. write an equation and solve

4

Step-by-step explanation:

Consecutive integers are  e.g.  1, 2, 3, 4, ...

So they are 1 units apart.

If we let one of the integers be "x", then the next consecutive one would be "x + 1".

x is the smaller

x + 1 is the larger

of the two...

Now,

The sum of smaller (x) and 2 TIMES larger (x + 1) is 14, so we can write:

We use algebra and solve for x:

So, the two numbers is 4  &  5

smaller of the two numbers is "4"

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2