What is the equation of a line that passes through the point (4, 2) and is perpendicular to the line whose equation is y=x3−1 ?

The equation of a line that passes through the point (4, 2) and is perpendicular to the line whose equation is y=x3−1  is

Step-by-step explanation:

Given:

point (4,2)

perpendicular line y =3x -1

To find:

equation of the line  =?

Solution:

We are given with perpendicular line . the slope of the perpendicular line will be negative, so let us take the reciprocal of the line and change its sign. bu doing so we will get,

slope  =

Now we know that the equation of the line is

y =mx+b----------------------(1)

where

m is the slope

b is the y intrcept

x,y are the points through which the line pass

so now substituting the values we get

b = 2 +1.3

b = 3.3

substituting in (1)

step-by-step explanation:

jjj

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .