Arocket is launched from the top of a 7ft platform. its initial velocity is 112 ft per sec. it is launched at an angle of 60° with respect to the ground. (a) find the rectangular equation that models its path. what type of path does the rocket follow

Parbolic path.

Step-by-step explanation:

This is bidimensional motion, so the equation that relates the vertical and horizontal position is:

Here, v₀, θ y g are constants, then we can rewrite (1) as:

where:

Therefore the rectangular equation will be:

This type of path is a parabolic motion.

I hope it helps you!

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!