Does there exist a di↵erentiable function g : [0, 1] r such that g'(x) = f(x) for all x 2 [0, 1]? justify your answer

No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Step-by-step explanation:

Assuming:  the function is in [0,1]

And rewriting it for the sake of clarity:

Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer

1) A function is considered to be differentiable if, and only if  both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:

2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]

The limit to the left

g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)

3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Because this is the same as to calculate the limit from the left and right side, of g(x).

This is what the Bilateral Theorem says:

its definatley   this on your answer choice?

e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)