Ahistogram of a sample of those arrival delays suggests that the distribution is skewed, not normal. how does the distribution affect the sample size?

a. the computed sample size should be divided by 2. b. the computed minimum sample size is not likely correct.

c. the computed minimum sample size is likely correct.

d. the computed sample size should be multiplied by 2.

look a the sides they are perpendicular

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

i don't think there is enough

1,2,4,5,10,11,20,22,44,55,110,220